Algebra II For Dummies. Sterling Mary Jane
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So, you can say
To simplify a radical expression such as
✔ (am)n = am · n: Raise a power to a power by multiplying the exponents.
✔
The second rule may look familiar – it’s one of the rules that govern changing from radicals to fractional exponents (see Chapter 4 for more on dealing with radicals and fractional exponents).
Here’s an example of how you apply the two rules when simplifying an expression:
Writing variables with negative exponents allows you to combine those variables with other factors that share the same base. For instance, if you have the expression
Implementing Factoring Techniques
When you factor an algebraic expression, you rewrite the sums and differences of the terms as a product. For instance, you write the three terms x2 – x – 42 in factored form as (x – 7)(x + 6). The expression changes from three terms to one big, multiplied-together term. You can factor two terms, three terms, four terms, and so on for many different purposes. The factorization comes in handy when you set the factored forms equal to zero to solve an equation. Factored numerators and denominators in fractions also make it possible to reduce the fractions.
You can think of factoring as the opposite of distributing. You have good reasons to distribute or multiply through by a value – the process allows you to combine like terms and simplify expressions. Factoring out a common factor also has its purposes for solving equations and combining fractions. The different formats are equivalent – they just have different uses.
To factor the expression 6x4 – 6x, for example, you first factor out the common factor, 6x, and then you use the pattern for the difference of two perfect cubes:
Keeping in mind my tip to start a problem off by looking for the greatest common factor, look at the example expression 48x3y2 – 300x3. When you factor the expression, you first divide out the common factor, 12x3, to get 12x3(4y2 – 25). You then factor the difference of perfect squares in the parentheses: 12x3(4y2 – 25) = 12x3(2y – 5)(2y + 5).
Here’s one more: The expression z4 – 81 is the difference of two perfect squares. When you factor it, you get z4 – 81 = (z2 – 9)(z2 + 9). Notice that the first factor is also the difference of two squares – you can factor again. The second term, however, is the sum of squares – you can’t factor it. With perfect cubes, you can factor both differences and sums, but not with the squares. So, the factorization of z4 – 81 is (z – 3)(z + 3)(z2 + 9).
You can often spot the greatest common factor with ease; you see a multiple of some number or variable in each term. With the product of two binomials, you either find the product or become satisfied that it doesn’t exist.
For example, you can perform the factorization of 6x3 – 15x2y + 24xy2 by dividing each term by the common factor, 3x: 6x3 – 15x2y + 24xy2 = 3x(2x2 – 5xy + 8y2).
Trinomials that factor into the product of two binomials have related powers on the variables in two of the terms. The relationship between the powers is that one is twice the other. When factoring a trinomial into the product of two binomials, you first look to see if you have a special product: a perfect square trinomial. If you