The Art of Mathematics in Business. Dr Jae K Shim

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The Art of Mathematics in Business - Dr Jae K Shim

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dolls. However, unforeseen competition has reduced sales to 1,500 dolls. The cost of its prediction error—that is, its failure to predict demand accurately, is calculated as follows:

      1.Initial predicted sales = 2,000 dollars

      Optimal decision: purchase 2,000 dollars

      Expected net income = $500 [(2,000 dollars × $0.40 contribution) − $300 fixed cost]

      2.Alternative parameter value = 1,500 dolls

      Optimal decision: purchase 1500 dollars

      Expected net income = $300 [(1,500 dollars × $0.40 contribution) − $300 fixed cost]

      3.Results of original decision under alternative parameter value Expected net income:

      Revenue (1,500 dolls × $1.00) – cost of dollars (2,000 dollars × $0.60) − $300 fixed cost = $1,500 – $1,200 – $300 = $0

      4.Cost of prediction error = (2) – (3) = $300

      How is it used and applied?

      It is important to determine the cost of the prediction error in order to minimize the potential detrimental effect of future profitability. The cost of the prediction error can be substantial, depending on the circumstances. For example, failure to make an accurate projection of sales could result in poor production planning, too much or too little purchase of labor, and so on, thereby causing potentially huge financial losses.

      Business people need to keep track of past prediction records to ensure that (1) future costs can be minimized and (2) better forecasting methods can be developed.

      Introduction

      The χ2 (chi-square) test is a statistical test of the significance of a difference between classifications or sub-classifications. The test is applied to sample data in testing whether or not two qualitative population variables are independent.

      How is the test performed?

      The χ2 test involves three steps.

      Step 1: Calculate the χ2 statistic, which is defined as:

image

      Where f0 = individual observed frequencies of each class

      fe = individual expected frequencies of each class

      Step 2. Find the table value at a given level of significance (see Table 6 in the Appendix).

      Step 3. If the calculated value is greater than the table value, we reject the full hypothesis, which means that the two variable are classifications are associated.

      Example

      Consider the following survey regarding restaurants:

image

      The null hypothesis is: The menu and the indoor/outdoor cafes are independent.

      In order to calculate χ2, we need to construct an expected value table on the basis of the assumption that menu and indoor/outdoor cafes are independent of each other. If no association exists, it is to be expected that the proportion of à la carte and prix fixe restaurants with outdoor cafes or tables will be the same as that without outdoor cafes. First, we compute the expected frequencies based on the premise of independence:

      635/844 = 0.7524209/844 = 0.2476

      Now, we can compute the expected values from the proportions of totals as follows:

      0.7524×646=486

      0.2476×646=160

      0.7524×198=149

      0.2476×198=049

      These expected values give the following table:

image

      Step 1. Calculate χ2. We are interested in how far the observed table differs from the expected table.

image

      =14.171

      Step 2. χ2 value at the 0.05 level of significance with one degree of freedom (from Table 6 in the Appendix) is 3.841. The degree of freedom is calculated as (no. rows − 1) × (no. of columns – 1) = (2 – 1) × (2 – 1) = 1.

      Step 3. As shown in Fig. 26.1, since the calculated value is greater than the table value (14.171 > 3.841), we reject the null hypothesis, which means that the menu is associated with the outdoor/indoor restaurant setup.

image

      How is it used and applied?

      The chi-square test has many applications in business. It is a statistical test of independence (or association), to determine if membership in categories of one variable is different as a function of membership in the categories of a second variable. It is important to note, however, that there are limitations to this test: (1) The sample must be big enough for the expected frequencies for each cell (rule of thumb: at least 5); and (2) the test does not tell anything about the direction of an association.

      Managers need to know whether the differences they observe among several sample proportions are significant or due only to chance. For example, marketing managers are concerned that their brand’s share may be unevenly distributed throughout the country. They conduct a survey in which the country is divided into specific number of geographic regions and see if consumer’s decisions as to whether or not to purchase the company’s brand has anything to do with the geographic location. As another example, a financial manager might be interested in the differences in capital structure within different firm sizes in a certain industry. To see if firm sizes have the same capital structure (or firm sizes have nothing to do with the capital structure), what he or she needs to do is to survey a group of firms with assets of different amounts and divide them into groups. Each firm can be classified according to predetermined debt/equity ratio groups.

       Part 4

       Managing Cash and Receivables

      Introduction

      Current profitability is only one important factor in success. Also essential is cash flow. In fact, a business can be profitable and still have a cash crisis. An example is a small business with a high level of credit sales but with a very long collection period. The business shows a profit but does not have the cash from those sales.

      It is

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