Quantum Mechanics, Volume 3. Claude Cohen-Tannoudji

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rel="nofollow" href="#ulink_6feccab3-a261-55ee-997b-eb502b191fa5">(A-10) gives:

       Comment:

acts. It can be easily verified that any permutation of the states simply multiply by its parity both members of the equality. It therefore remains valid independently of the order chosen for the individual states in the initial ket.

      We now study the Hermitian conjugate operator of

, that we shall simply call aui since taking twice in a row the Hermitian conjugate of an operator brings you back to the initial operator.

      A-3-a. Bosons

      For bosons, we deduce from (A-16) that the only non-zero matrix elements of

in the Fock states orthonormal basis are:

      They link two vectors having equal occupation numbers except for ni, which increases by one going from the ket to the bra.

are obtained from relation (A-20), using the general definition (B-49) of Chapter II. The only non-zero matrix elements of aui are thus:

      (A-21)

      Since the basis we use is complete, we can deduce the action of the operators ai on kets having given occupation numbers:

      (note that we have replaced ni by ni — 1). As opposed to

, which adds a particle in the state |ui〉, the operator aui takes one away; it yields zero when applied on a ket where the state |ui〉 is empty to begin with, such as the vacuum state:

      We call auithe annihilation operator” for the state |ui〉.

      A-3-b. Fermions

      For fermions, relation (A-18) allows writing the matrix elements:

      (A-24)image

      The only non-zero elements are those where all the individual occupied states are left unchanged in the bra and the ket, except for the state ui only present in the bra, but not in the ket. As for the occupation numbers, none change, except for ni which goes from 0 (in the ket) to 1 (in the bra).

      The Hermitian conjugation operation then yields the action of the corresponding annihilation operator:

      or, if initially the state |ui〉 is not occupied:

       Comment:

      (A-27)image

      For fermions, the operators a and a therefore act on the individual state that is listed in the first position in the N-particle ket; a destroys the first state in the list, and at creates a new state placed at the beginning of the list. Forgetting this could lead to errors in sign.

      Consider the operator image defined by:

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