Geochemistry. William M. White

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simplest equation of state that takes account of these factors. The van der Waals equation is:

      (2.14)equation

      Here again we have converted volume from an extensive to an intensive property by dividing by N.

      Let's examine the way in which the Van der Waals equation attempts to take account of finite molecular volume and forces between molecules. Considering first the forces between molecules, imagine two volume elements v1 and v2. The attractive forces will be proportional to the number of molecules or the concentrations, c1 and c2, in each. Therefore, attractive forces are proportional to images. Since c is the number of molecules per unit volume, images, we see that attractive forces are proportional to images. The a term is a constant that depends on the nature and strength of the forces between molecules, and will therefore be different for each type of gas.

       2.3.2.2 Other equations of state for gases

      The Redlich-Kwong equation (1949) expresses the attractive forces as a more complex function:

      (2.15)equation

      The Virial equation is much easier to handle algebraically than the van der Waals equation and has some theoretical basis in statistical mechanics:

      (2.16)equation

Gas a liter-atm/mole2 b liter/mole
Helium 0.034 0.0237
Argon 1.345 0.0171
Hydrogen 0.244 0.0266
Oxygen 1.360 0.0318
Nitrogen 1.390 0.0391
Carbon dioxide 3.592 0.0399
Water 5.464 0.0305
Benzene 18.00 0.1154

      2.3.3 Equation of state for other substances

      The compressibility and coefficient of thermal expansion parameters allow us to construct an equation of state for any substance. Such an equation relates the fundamental properties of the substance: its temperature, pressure, and volume. The partial differential of volume with respect to temperature and pressure is such an equation:

      Substituting the coefficient of thermal expansion and compressibility for ∂V/∂T and ∂V/∂P respectively we have:

      (2.19)equation

      where V0 is the volume at some reference point where τ = 0 (Figure 2.3a) and γ is a scale factor. For example, we might choose τ = 0 to be the freezing point of water and the scale factor such that γ = 100 (Figure 2.3b) occurs at the boiling point of water, as is the case in the centigrade scale. Rearranging, we have:

      Then τ = 0 at V = V0. If V is less than the reference volume, then temperature will be negative on our scale. But notice that while any positive value of temperature is possible on this scale, there is a limit to the range of possible negative values. This is because V can never be negative. The minimum value of temperature on this scale will occur when V is 0. This occurs at:

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