Geochemistry. William M. White

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      Notice the similarity to the Helmholtz free energy; in that case we subtracted the TS term from the internal energy; in this case we subtracted the TS term from the enthalpy. The Gibbs free energy is the energy available for nonPV work (such as chemical work). It has two other important properties: its independent variables are T and P, generally the ones in which we are most interested in geochemistry, and it contains the entropy term (as does the Helmholtz free energy), and hence can be used as an indication of the direction in which spontaneous reactions will occur.

       2.11.2.2 Gibbs free energy change in reactions

      For a finite change at constant temperature, the Gibbs free energy change is:

      (2.125)equation

      The free energy change of formation, images, is related to the enthalpy and entropy change of reaction:

      (2.126)equation

      Like other properties of state, the Gibbs free energy is additive. Therefore:

      (2.127)equation

      In other words, we can use Hess's law to calculate the free energy change of reaction. Values for images at the standard state are available in compilations.

      2.11.3 Criteria for equilibrium and spontaneity

      The Gibbs free energy is perhaps the single most important thermodynamic variable in geochemistry because it provides this criterion for recognizing equilibrium. This criterion is:

       Products and reactants are in equilibrium when their Gibbs free energies are equal.

      Another important quality of the Gibbs free energy is closely related:

       At fixed temperature and pressure, a chemical reaction will proceed in the direction of lower Gibbs free energy (i.e., ΔG r <0).

      2.11.4 Temperature and pressure dependence of the Gibbs free energy

      One reason why the Gibbs free energy is useful is that its characteristic variables are temperature and pressure, which are the “external” variables of greatest interest in geochemistry. Since it is a state variable, we can deduce its temperature and pressure dependencies from eqn. 2.124, which are:

      Using the thermodynamic data given in Table 2.2, calculate ΔGr for the reaction:

equation equation

      at 298 K and 0.1 MPa. Which mineral assemblage is more stable under these conditions (i.e., which side of the reaction is favored)? Which assemblage will be favored by increasing pressure? Why? Which side will be favored by increasing temperature? Why?

      Answer: We can calculate ΔGr from ΔHf and ΔSf, values listed in Table 2.2:

equation

      ΔH is calculated as: images. ΔS is calculated in a similar manner. Our result is −6.08 kJ/mol. Because ΔGr is negative, the reaction will proceed to the right, so that the assemblage on the right is more stable under the conditions of 298 K and 1 atm.

      To find out which side will be favored by increasing pressure and temperature, we use equations 2.128 and 2.129 to see how ΔG will change. For temperature, images. ΔSr is −36.37 J/K-mol, and images. The result is positive, so that ΔG will increase with increasing T, favoring the left side. Had we carried out the calculation at 1000°C and 0.1 MPa, a temperature appropriate for crystallization from magma, we would have found that the anorthite–forsterite assemblage is stable. For pressure, images. ΔV for the reaction is −20.01 cc/mol (= J/MPa-mol), so will decrease with increasing pressure, favoring the right side. Reassuringly, our thermodynamic result is consistent with geologic observation. The assemblage on the left, which could be called plagioclase peridotite, transforms to the assemblage on the right, spinel peridotite, as pressure increases in the mantle.

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