Set Theory And Foundations Of Mathematics: An Introduction To Mathematical Logic - Volume I: Set Theory. Douglas Cenzer

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so that xAB. Thus AAB. Next suppose that xAB. Then xAxB, so certainly xA. Thus ABA. It follows that AB = A, as desired.

      (2)

(1): Suppose that AB = A. Let x be arbitrary and suppose that xA. Since AB = A, it follows that xAB. That is, xAxB, so that xB. Hence AB.

      

      We will sometimes write A \ B for AB. The proof of the following is left as an exercise.

      Proposition 2.1.9. The following conditions are equivalent:

      (1) AB;

      (2) BA;

      (3) A \ B =

.

      There are some interactions between the inclusion relation and the Boolean operations, in the same way that inequality for numbers interacts with the addition and multiplication operations.

      Proposition 2.1.10. For any sets A, B, and C, we have the following properties:

      (1) If BA and CA, then BCA.

      (2) If AB and AC, then ABC.

      Proof. (1) Assume that BA and CA. Let x be arbitrary and suppose that xBC. This means that xBxC. There are two cases. Suppose first that xB. Since BA, it follows that xA. Suppose next that xC. Since CA, it follows again that xA. Hence xBCxA. Since x was arbitrary, we have BCA, as desired.

      The proof of part (2) is left to the exercises.

       Exercises for Section 2.1

      Exercise 2.1.1. Prove the Commutative Law for intersection, that is, for any sets A and B, AB = BA.

      Exercise 2.1.2. Prove the Associative Law for union, that is, for any sets A, B, and C, A ∪ (BC) = (AB) ∪ C.

      

      Exercise 2.1.3. Prove the Distributive Laws, that is, for any sets A, B, and C, A ∪ (BC) = (AB) ∩ (AC) and A ∩ (BC) = (AB) ∪ (AC).

      Exercise 2.1.4. Show that, for any set A,

A and AU.

      Exercise 2.1.5. Show that, for any set A, (A) = A.

      Exercise 2.1.6. Show that, for any set A, A

= A and AU = A.

      Exercise 2.1.7. Show that, for any set A, A

=
and AU = U.

      Exercise 2.1.8. Complete the argument that the relation ⊆ is a partial ordering by showing that it is transitive, that is, if AB and BC then AC.

      Exercise 2.1.9. Show that, for any sets A and B, AB if and only if AB = B.

      Exercise 2.1.10. Show that the following conditions are equivalent:

      (1) AB;

      (2) BA;

      (3) A \ B =

.

      Exercise 2.1.11. Show that, for any sets A, B, and C, AB and AC imply that ABC.

      Relations play a fundamental role in mathematics. Of particular interest are orderings, equivalence relations, and graphs. The notion of a graph is quite general. That is, a graph G = (V, E) is simply a set V of vertices and a binary relation E. In a directed graph, a pair (u, v) is said to be an edge from u to v.

      A key notion here is that of an ordered pair. Given two elements a1, a2 from our universe U, the ordered pair (a1, a2) is defined so that for any two pairs of elements (a1, b1) and (b1, b2), (a1, a2) = (b1, b2)

a1 = b1 and a2 = b2. This will be defined carefully in Chapter 3, along with the notion of an n-tuple (a1, . . . , an) of elements.

      Definition 2.2.1. Let A and B be sets.

      (1) The product of A and B is defined to be

      (2) An = {(a1, . . . , an) : each aiA}. Here (a1, . . . , an) is called an n-tuple.

      (3) A subset R of A×B is called a relation, specifically a binary relation.

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