Hydraulic Fluid Power. Andrea Vacca

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Hydraulic Fluid Power - Andrea Vacca

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piston diameter.

      2 Decrease the valve size, thus reducing the valve coefficient k.

      3 Reduce the accumulator pressure.

      4 Add an orifice in series with the valve (see figure below).

      All mentioned solutions are reasonable; however, solutions 1, 2, and 3 require modifications to the existing components. Solution 4 can be a simple way to modify an existing system.

Schematic illustration of the system that contains a solenoid valve and when energized opens an accumulator to the piston chamber of a linear accumulator. upper Q equals StartFraction pi dot d Subscript e q Superscript 2 Baseline Over 4 EndFraction dot upper C Subscript f Baseline dot StartRoot StartFraction 2 left-parenthesis p Subscript a c c Baseline minus p Subscript c y l Baseline right-parenthesis Over rho EndFraction EndRoot

      deq is the diameter of the equivalent orifice given by the series connection of SV and O2. The desired speed of the actuator corresponds to the following flow:

upper Q 2 equals ModifyingAbove x With dot Subscript 2 Baseline dot StartFraction pi dot upper D squared Over 4 EndFraction equals 0.6 dot 0.08 left-bracket m slash s right-bracket dot StartFraction pi dot left-parenthesis 0.15 right-parenthesis squared left-bracket m squared right-bracket Over 4 EndFraction dot 60 000 equals 50.9 l slash min

      The equivalent series orifice diameter results:

d Subscript e q Baseline equals NestedStartRoot StartFraction 4 dot upper Q 2 Over pi dot upper C Subscript f Baseline dot StartRoot StartFraction 2 left-parenthesis p Subscript a c c Baseline minus p Subscript c y l Baseline right-parenthesis Over rho EndFraction EndRoot EndFraction NestedEndRoot equals NestedStartRoot StartFraction 4 dot 50.9 slash 60 000 left-bracket m cubed slash s right-bracket Over pi dot 0.7 dot StartRoot StartFraction 2 dot left-parenthesis 100 minus 28.3 right-parenthesis dot 10 Superscript 5 Baseline left-bracket upper N slash m squared right-bracket Over 850 left-bracket italic k g slash m cubed right-bracket EndFraction EndRoot EndFraction NestedEndRoot equals 3.44 italic m m

      Assuming that both orifices have the same flow coefficient (Cf = 0.7), the diameter of orifice O2 results:

normal d Subscript upper O Baseline 2 Baseline equals left-parenthesis StartStartFraction 1 OverOver StartFraction 1 Over normal d Subscript e q Superscript 4 Baseline EndFraction minus StartFraction 1 Over normal d Subscript upper O Superscript 4 Baseline EndFraction EndEndFraction right-parenthesis Superscript 1 slash 4 Baseline equals left-parenthesis StartStartFraction 1 OverOver StartFraction 1 Over left-parenthesis 3.4 left-bracket italic m m right-bracket right-parenthesis Superscript 4 Baseline EndFraction minus StartFraction 1 Over left-parenthesis 4.4 left-bracket italic m m right-bracket right-parenthesis Superscript 4 Baseline EndFraction EndEndFraction right-parenthesis Superscript 1 slash 4 Baseline equals 3.86 italic m m

      Even though the orifice element is described by a single equation (Eq. (4.5)), an orifice can assume different roles in a hydraulic circuit. A first way to classify an orifice function is based on its location in the system: in fact, orifices can be present either in the working and return lines or on the pilot lines of the systems. The working and return lines are represented by the connections to/from the actuators of the system; the power transfer functions achieved by the system occur in these lines. Thus, these lines are usually characterized by significant values of flow rate and pressure. Pilot lines are instead used to transmit pressure information to different locations of the system. These latter lines usually have negligible flow rates and are used for control purposes. According to ISO1219‐1 [1], pilot lines are always indicated with dashed lines, while working and return lines with a solid line.

      4.5.1 Orifices in Pressure and Return Lines

      When an orifice is used in the working or the return line of a system, it can operate as metering or compensating element.

      This classification is important to understand several control strategies used in hydraulic systems, as it will be shown in Part II and Part III of the book. A significant example is now provided to clarify the distinction between these different behaviors of an orifice.

      Example 4.3 Orifice as a Metering Element or a Compensator

      The system in figure consists of a fixed displacement pump and a variable orifice in parallel with a pressure relief valve. The pressure relief valve limits the maximum pressure at the pump outlet to p*. The pump delivers a fixed flow rate QP independently of the pump outlet pressure. Find the flow rate through the orifice, QO, as well as the pump outlet pressure pP, as a function of the orifice area opening, Ω. Describe also the function of the orifice, which can either be metering or compensator.

"Schematic illustration of a fixed displacement pump and a variable orifice in parallel with a pressure relief valve."

       Given:

      The pump flow rate, QP; the setting of the relief valve p*.

       Find:

      1 The flow rate through the orifice, QO

      2 The pressure at pump outlet, pP

      3 The orifice function (metering/compensator)

      Solution:

      Point P is located at the junction of the three main elements of the system (the pump, the relief valve, the variable orifice). Therefore, the operating pressure at point P can be found by intersecting the characteristics curves of these components, while also satisfying the constraints of maximum allowed pressure and available flow.

      To clarify this statement, the characteristic curves of the three components in the (Δp, Q) chart are shown in the figure below. In particular,

       the orifice characteristic curves are plotted according to the orifice equation 4.5 for decreasing values of the area Ω (Ω1 > Ω2 > Ω3…). This trend is as also shown in the plot of Figure

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