Mathematics for Enzyme Reaction Kinetics and Reactor Performance. F. Xavier Malcata
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If the exponent of cosine in Eq. (2.388) is an odd integer, say, 2n+1, then one gets
upon replacement of n by 2n + 1, and accordingly of i by 2i + 1; the summation was meanwhile rewritten as two consecutive summations, while z in the first summation gave the floor to its reciprocal at the expense of taking the negative of the exponent. A new change of variable, viz.
– inspired on Eq. (2.392), proves useful to transform the second summation in Eq. (2.398) to
where condensation of terms alike meanwhile took place; Eq. (2.391) may then be used to transform Eq. (2.400) to
– while insertion of Eq. (2.401) in Eq. (2.398) further leads to
with summations pooled together on the basis of their similarity, and
where 2 was meanwhile factored out in the exponents; in view of Eq. (2.383) again – after exchanging exponent n by 2(n − i) + 1, one finds
as alternative version of Eq. (2.403) – also with the aid of 22n being identical to the nth power of 22. Since 2 can cancel out between numerator and denominator, Eq. (2.404) becomes simply
after renaming angle θ to x (expressed in rad); all in all, an integer power of the cosine of an angle x may be expressed as a (finite) sum of cosines of integer multiples of x – see Eqs. (2.397) and (2.405).
With regard to the power of any sine, Eq. (2.386) may be similarly revisited with the aid of Newton’s binomial, labeled as Eq. (2.236), to get
(2.406)
lumping of the powers of z and 1/z supports transformation to
Should the exponent of sine be an even integer, Eq. (2.407) transforms to
once n and i are replaced by 2n and 2i, respectively – where terms were deliberately grouped according to 2i < n, 2i = n and 2i > n, and variable z swapped for 1/z at the expense of a minus sign in the original exponent; variable 2j as per Eq. (2.392) may now be retrieved to rewrite the second summation as
after taking Eq. (2.391) into account and performing elementary algebraic rearrangement. Insertion of Eq. (2.409), together with realization that (−1)2n−2j = (−1)2n (−1)−2j = (−1)−2j = (−1)2j (since 2n and 2j are even integers) and z0 = 1, allow transformation of Eq. (2.408) to
with convenient factoring out of