Quantum Mechanics, Volume 3. Claude Cohen-Tannoudji

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only if l = 1; it is then orthogonal to image if k ≠ 1. Consequently, the only term left in the summation corresponds to k = l = 1. As the operator image multiplies the ket by its population N, we get:

      With the same argument, we can write:

      In this case, for the second matrix element to be non-zero, both subscripts m and n must be equal to 1 and the same is true for both subscripts k and l (otherwise the operator will yield a Fock state orthogonal to image). When all the subscripts are equal to 1, the operator multiplies the ket image by N (N — 1). This leads to:

      The average interaction energy is therefore simply the product of the number of pairs N(N —1)/2 that can be formed with N particles and the average interaction energy of a given pair.

      Consider a variation of |θ〉:

      where |δα〉 is an arbitrary infinitesimal ket of the individual state space, and χ an arbitrary real number. To ensure that the normalization condition (6) is still satisfied, we impose |δα〉 and |θ〉 to be orthogonal:

      (37)image

      The stationarity condition for image must hold for any arbitrary real value of χ. As before (§ 2-b-α), it follows that both δc1 and δc2 are zero. Consequently, we can impose the variation image to be zero as just the bra 〈ι| varies (but not the ket |θ〉), or the opposite.

      Varying only the bra, we get the condition:

      (38)image

      which leads to:

      (42)image

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