Quantum Mechanics, Volume 3. Claude Cohen-Tannoudji

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Quantum Mechanics, Volume 3 - Claude Cohen-Tannoudji

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3-c Critical velocity, metastable flow 3-d Generalization; topological aspects

      In this complement, we return to the calculations of Complement CXV, concerning a system of bosons all in the same individual state. We now consider the more general case where that state is time-dependent. Using a variational method similar to the one we used in Complement CXV, we shall study the time variations of the N-particle state vector. This amounts to using a time-dependent mean field approximation. We shall establish in § 1 a time-dependent version of the Gross-Pitaevskii equation, and explore some of its predictions such as the small oscillations associated with Bogolubov phonons. In § 2, we shall study local conservation laws derived from this equation for which we will give a hydrodynamic analogy, introducing a characteristic relaxation length. Finally, we will show in § 3 how the Gross-Pitaevskii equation predicts the existence of metastable flows and superfluidity.

      but we now suppose that the individual ket |θ〉 is a function of time |θ(t)〉. The creation operator image in the corresponding individual state is then time-dependent:

      (2)image

      We will let the ket |θ(t)〉 vary arbitrarily, as long as it remains normalized at all times:

      Let us introduce the functional of |Ψ(t)〉:

      (5)image

      The only term left to be computed in (4) contains the time derivative.

      This term includes the diagonal matrix element:

      For an infinitesimal time dt, the operator image is proportional to the difference image, hence to the difference between two creation operators associated with two slightly different orthonormal bases. Now, for bosons, all the creation operators commute with each other, regardless of their associated basis. Therefore, in each term of the summation over k, we can move the derivative of the operator to the far right, and obtain the same result, whatever the value of k. The summation is therefore equal to N times the expression:

      Now, we know that:

      (8)image

      (9)image

      Regrouping all these results, we finally obtain:

      (10)image

      We now make an infinitesimal variation of |θ(t)〉:

      (11)image

      in order to find the kets |θ(t)〉 for which the previous expression will be stationary. As in the search for a stationary state in Complement CXV, we get variations coming from the infinitesimal ket eiχ |δθ(t)〉 and others from the infinitesimal bra e–iχδθ(t)|; as χ is chosen arbitrarily, the same argument as before leads us to conclude that each of these variations must be zero. Writing only the variation associated with the infinitesimal bra, we see that the stationarity condition requires |θ(t)〉 to be a solution of the following equation, written for |φ(t)〉:

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