Quantum Mechanics, Volume 3. Claude Cohen-Tannoudji

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      the differential equation can be written as:

      (30)image

      that is:

      (31)image

      The solution of this equation is:

      (the opposite value is also a solution, as expected since we calculate at the same time the evolution of image and of its complex conjugate; we only use here the positive value). Setting:

      (33)image

       β. Discussion

      (35)image

      (36)image

      Consequently, the excitation spectrum we have calculated corresponds to density waves propagating in the system with a phase velocity w(k)/k.

      In the absence of interactions, (g = k0 = 0), this spectrum becomes:

      which simply yields the usual quadratic relation for a free particle. Physically, this means that the boson system can be excited by transferring a particle from the individual ground state, with wave function φ0 (r) and zero kinetic energy, to any state φk(r) having an energy ħ2k2/2m.

      In the presence of interactions, it is no longer possible to limit the excitation to a single particle, which immediately transmits it to the others. The system’s excitations become what we call “elementary excitations”, involving a collective motion of all the particles, and hence oscillations in the density of the boson system. If kk0, we see from (34) that:

      (38)image

      where c is defined as:

      (40)image

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