Quantum Mechanical Foundations of Molecular Spectroscopy. Max Diem

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Quantum Mechanical Foundations of Molecular Spectroscopy - Max Diem

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desired energy eigenvalues. The eigenfunctions typically form an n‐dimensional vector space in which the eigenvalues appear along the diagonal. Thus, Eq. (2.20) implies

      that is, the Hamiltonian operating on a set of eigenfunctions such that

      2.3.2 Solution of the Particle‐in‐a‐Box Schrödinger Equation

      Rearranging Eqs. (2.19) and (2.20) yields

      (2.22)left-brace minus StartFraction normal h with stroke squared Over 2 m EndFraction StartFraction d squared Over normal d x squared EndFraction right-brace normal psi left-parenthesis x right-parenthesis equals upper E normal psi left-parenthesis x right-parenthesis

      which is a simple differential equation that can be used to obtain the eigenfunctions ψ(x):

      could be solution of the differential Eq. (2.23),

      since

      (2.25)StartFraction normal d squared y Over normal d x squared EndFraction equals minus upper A b squared cosine italic b x

      Here, the term b2 would correspond to 2mE / ħ2, and A is a yet undefined amplitude factor. Similarly,

      and

      (2.28)StartFraction d squared Over normal d x squared EndFraction normal psi left-parenthesis x right-parenthesis equals minus upper A StartFraction 2 italic m upper E Over normal h with stroke squared EndFraction sine left-parenthesis StartFraction 2 italic m upper E Over normal h with stroke squared EndFraction right-parenthesis Superscript one half Baseline x equals minus upper A StartFraction 2 italic m upper E Over normal h with stroke squared EndFraction normal psi left-parenthesis x right-parenthesis

      (2.29)normal psi left-parenthesis x right-parenthesis equals 0 a t x equals 0 and a t x equals upper L

      Because of these conditions, the cosine function proposed as possible solutions (Eq. [2.24]) of Eq. (2.23) was rejected, since the cosine function is nonzero at x = 0. Because of the required continuity at x = L, the value of the function

normal psi left-parenthesis x right-parenthesis equals upper A sine left-parenthesis StartFraction 2 italic m upper E Over normal h with stroke squared EndFraction right-parenthesis Superscript one half Baseline x

      must be zero at x = L as well. This can happen in two ways: The first possibility occurs if the amplitude A is zero. This case is of no further interest, since a zero amplitude of the wavefunction would imply that the particle is not inside the box. The second possibility for the wavefunction to be zero at x = L occurs if

      (2.30)

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