Finite Element Analysis. Barna Szabó

Чтение книги онлайн.

Читать онлайн книгу Finite Element Analysis - Barna Szabó страница 49

Автор:
Жанр:
Серия:
Издательство:
Finite Element Analysis - Barna Szabó

Скачать книгу

alt="left-parenthesis omega Subscript upper F upper E Baseline slash omega Subscript upper E upper X Baseline right-parenthesis Subscript n"/> against n slash upper N, where n is the nth eigenvalue, then we get the curves shown in Fig. 1.13. The curves show that somewhat more than 20% of the numerically computed eigenvalues will be accurate. The higher eigenvalues cannot be well approximated in the space upper S Superscript 0 Baseline left-parenthesis upper I right-parenthesis. The existence of the jump seen at n slash upper N equals 0.5 is a feature of numerically approximated eigenvalues by means of standard finite element spaces using the h‐version [2]. The location of the jump depends on the polynomial degree of elements. There is no jump when p equals 1.

Graph depicts the ratio (ωFE/ωEX)n corresponding to the h version, p=2.
corresponding to the h version,
.

      It is possible to reduce this error by enforcing the continuity of derivatives. Examples are available in [32]. There is a tradeoff, however: Enforcing continuity of derivatives on the basis functions reduces the number of degrees of freedom but entails a substantial programming burden because an adaptive scheme has to be devised for the general case to ensure that the proper degree of continuity is enforced. If, for example, μ would be a piecewise constant function then the continuity of the first and higher derivatives must not be enforced in those points where μ is discontinuous.

Graph depicts the ratio (ωFE/ωEX)n corresponding to the p version. Uniform mesh, 5 elements.
corresponding to the p version. Uniform mesh, 5 elements.

p 5 10 15 20
ω 24 194.296 100.787 98.312 98.312

      Any eigenvalue can be approximated to an arbitrary degree of precision on a suitably defined mesh and uniform increase in the degrees of freedom. When κ and/or mu are discontinuous functions then the points of discontinuity must be node points.

      Observe that the numerically computed eigenvalues converge monotonically from above. This follows directly from the fact that the eigenfunctions are minimizers of the Rayleigh quotient.

      Exercise 1.22 Find the eigenvalues for the problem of Example 1.15 using the generalized formulation and the basis functions phi Subscript n Baseline left-parenthesis x right-parenthesis equals sine left-parenthesis n pi x slash script l right-parenthesis, (n equals 1 comma 2 comma ellipsis comma upper N). Assume that κ and mu

Скачать книгу