Algorithms in Bioinformatics. Paul A. Gagniuc

Чтение книги онлайн.

Читать онлайн книгу Algorithms in Bioinformatics - Paul A. Gagniuc страница 21

Algorithms in Bioinformatics - Paul A. Gagniuc

Скачать книгу

of chromosomes/cell). For a diploid cell (2n = 46 Chr), the linear length of all 46 dsDNA molecules is calculated as above and the result in multiplied by two:

equation

      Additional algorithm 2.1 Note that the source code is in context and works with copy/paste.

      <script> document.write('Homo sapiens (3100 Mb): <br>'); document.write('DNA in a haploid cell nucleus: '); document.write(f(3100) + ' meters<br>'); document.write('DNA in a somatic cell nucleus: '); document.write((2 * f(3100)) + ' meters<br>'); function f(Mb){return (0.34 * 1000000 * Mb)/1000000000;} </script>Output: Homo sapiens (3100 Mb): DNA in a haploid cell nucleus: 1.054 meters DNA in a somatic cell nucleus: 2.108 meters

      Additional algorithm 2.2 Note that the source code is in context and works with copy/paste.

      <script> // DNA to meters var a = 'Ambystoma mexicanum|32396Mb' + 'Pinus lambertiana|27603Mb' + 'Sequoia sempervirens|26537Mb' + 'Minicystis rosea|16Mb' + 'Sorangium cellulosum So0157-2|14.78Mb' + 'Escherichia coli|4.9Mb' + 'Encephalitozoon intestinalis|2.3Mb' + 'Ostreococcus tauri|12.6Mb' + 'Homo sapiens|3100Mb'; var t = a.split('Mb'); for (var u=0; u<t.length-1; u ++) { var r = t[u].split('|'); document.write(r[0] + ' (' + r[1] + ' Mb) = '); document.write(f(r[1]) + ' meters<br>'); } function f(Mb){return (0.34 * 1000000 * Mb)/1000000000;} </script> Output: Ambystoma mexicanum (32396 Mb) = 11.01464 meters Pinus lambertiana (27603 Mb) = 9.38502 meters Sequoia sempervirens (26537 Mb) = 9.02258 meters Minicystis rosea (16 Mb) = 0.00544 meters Sorangium cellulosum So0157-2 (14.78 Mb) = 0.0050252 meters Escherichia coli (4.9 Mb) = 0.0016660000000000002 meters Encephalitozoon intestinalis (2.3 Mb) = 0.0007819999999999999 meters Ostreococcus tauri (12.6 Mb) = 0.004284 meters Homo sapiens (3100 Mb) = 1.054 meters

      2.3.3 Computations on the Average Genome Size

Schematic illustration of the average genome size. (a) Shows the proportion of known species in each kingdom of life. (b) It shows the tree of life with data on the main kingdoms of life. Each kingdom is labeled with the average genome size and the average GC% content. (c) Shows the average organellar genome for a number of organelles investigated to date. Here, the organelles are sorted by GC%. (d) It shows a comparison between mitochondria and chloroplasts. (e) Shows a comparison between plasmids from bacteria, archaea, and eukaryotes. For each chart (c–e), the left axis indicates the GC% percentage and the right axis indicates the average size of the genome expressed in mega base pairs.
Genome size average (Mb)
Eukaryotes (Mb)

Скачать книгу