Properties for Design of Composite Structures. Neil McCartney

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t Baseline Over upper E Subscript normal upper T Baseline EndFraction plus StartFraction nu Subscript normal a Baseline nu Subscript normal upper A Baseline Over upper E Subscript normal upper A Baseline EndFraction right-parenthesis equals nu overTilde Subscript normal t Baseline comma"/>(2.224)

      so that (2.223) may now be written as

      Integration with respect to x3 then leads to

      As the shear stresses σ13 and σ23 are everywhere zero, it follows from (2.143), (2.209) and (2.211) that

      StartFraction partial-differential u 3 Over partial-differential x 1 EndFraction equals minus StartFraction partial-differential u 1 Over partial-differential x 3 EndFraction equals minus ModifyingAbove epsilon With caret Subscript normal upper A Baseline x 1 comma StartFraction partial-differential u 3 Over partial-differential x 2 EndFraction equals minus StartFraction partial-differential u 2 Over partial-differential x 3 EndFraction equals minus ModifyingAbove epsilon With caret Subscript normal upper T Baseline x 2 period(2.227)

      Integration then yields

      u 3 equals minus one-half ModifyingAbove epsilon With caret Subscript normal upper A Baseline x 1 squared plus g 1 left-parenthesis x 2 comma x 3 right-parenthesis comma u 3 equals minus one-half ModifyingAbove epsilon With caret Subscript normal upper T Baseline x 2 squared plus g 2 left-parenthesis x 1 comma x 3 right-parenthesis period(2.228)

      These relations must be consistent with (2.226) so that

      where the displacement component has been selected to be zero at the origin.

      The through-thickness displacement of the top surface of the beam, at x3=0, can be defined in terms of two lengths, R1 and R2, which are the radii of curvature of this surface in the x1x3 plane and the x2x3 plane, respectively. The exact relationships are given by the well-known formulae

      StartFraction 1 Over upper R 1 EndFraction equals minus StartStartFraction StartFraction partial-differential squared u 3 Over partial-differential x 1 squared EndFraction OverOver left-bracket 1 plus left-parenthesis StartFraction partial-differential u 3 Over partial-differential x 1 EndFraction right-parenthesis squared right-bracket Superscript 3 slash 2 Baseline EndEndFraction comma StartFraction 1 Over upper R 2 EndFraction equals minus StartStartFraction StartFraction partial-differential squared u 3 Over partial-differential x 2 squared EndFraction OverOver left-bracket 1 plus left-parenthesis StartFraction partial-differential u 3 Over partial-differential x 2 EndFraction right-parenthesis squared right-bracket Superscript 3 slash 2 Baseline EndEndFraction period(2.230)

      For small deflections

      StartFraction 1 Over upper R 1 EndFraction equals minus StartFraction partial-differential squared u 3 Over partial-differential x 1 squared EndFraction comma StartFraction 1 Over upper R 2 EndFraction equals minus StartFraction partial-differential squared u 3 Over partial-differential x 2 squared EndFraction period(2.231)

      Thus, it follows from (2.229) that

      upper R 1 equals StartFraction 1 Over ModifyingAbove epsilon With caret Subscript normal upper A Baseline EndFraction comma upper R 2 equals StartFraction 1 Over ModifyingAbove epsilon With caret Subscript normal upper T Baseline EndFraction comma(2.232)

      providing a useful physical interpretation of the strain parameters ε^A and ε^T.

      The final requirement is to determine the loading state that is consistent with the various strain parameter values. It is assumed that stresses within the beam can arise from an applied in-plane loading that is equivalent to an applied axial force FA and a transverse force FT acting in the mid-plane between the upper and lower surfaces of the beam, and an axial applied bending moment per unit area of cross section MA and a transverse applied bending moment per unit area of cross section MT. From mechanical equilibrium