Invariants And Pictures: Low-dimensional Topology And Combinatorial Group Theory. Vassily Olegovich Manturov

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the invariance under the third Reidemeister move. Let β be a braid word, β1 = βζiζi+1ζi and β2 = βζi+1,ζiζi+1. Let p, q, r be the global numbers of strands occupying positions n, n + 1, n + 2 at the bottom of β.

      Denote f(β) by (P1, . . . , Pn), f(β1) by figure, and f(β2) by figure. Obviously, ∀ip, q, r we have figure. Direct calculations show that figure and figure.

      Now, let us consider the mixed move by using the same notation: β1 = βζiζi+1σi, β2 = σi+1ζiζi+1. As before, figure for all jp, q, r. Now, direct calculation shows that

      and

      Finally, consider the “classical” case figure; the notation is the same. Again figure. Besides this, since the p-th strand forms two overcrossings in both cases then figure. Then,

      and

      As we see, the final results coincide and this completes the proof of the theorem.

      Thus, we have proved that f is a virtual braid invariant; i.e., for a given braid B the value of f does not depend on the diagram representing B. So, we can write simply f(B).

      Remark 2.3. In fact, we can think of f as a function valued not in (E1, . . . , En), but in n copies of G: all these invariants were proved for the general case of (G, . . . , G). The present construction of (E1, . . . , En) is considered for the sake of simplicity.

      Classical braids (i.e., braids without virtual crossings) can be considered up to two equivalences: classical (modulo only classical moves) and virtual (modulo all moves). Now, we prove that they are the same. This fact is not new. It follows from [Fenn, Rimanyi and Rourke, 1997]. An elementary proof was given in [Manturov, 2016b].

      Theorem 2.6. Two virtually equal classical braids B1 and B2 are classically equal.

      Proof. Since B1 is virtually equal to B2, we have f(B1) = f(B2). Now, taking into account that f is a complete invariant on the set of classical braids, we have B1 = B2 (in the classical sense).

      As in the case of virtual knots, in the case of virtual braids there exists a forbidden move, namely, figure. Now, we are going to show that it cannot be represented by a finite sequence of the virtual braid group relations.

      Theorem 2.7. A forbidden move (relation) cannot be represented by a finite sequence of legal moves (relations).

      

      Proof. Actually, let us calculate the values f(σ1σ2ζ1) and f(ζ2σ1σ2). In the first case we have:

      In the second case we have:

      As we see, the final results are not the same (i.e., they represent different virtual n-systems); thus, the forbidden move changes the virtual braid.

      Remark 2.4. If we put t = 1, the results f(X) and f(Y) become the same. Thus that is the variable t that “feels” the forbidden move.

      2.4.2.1A 2n-variable generalisation of the invariant

      In the present section we define a stronger version of the f invariant described in the previous section. This generalised invariant was invented by V. O. Manturov soon after the paper [Chterental, 2015] was published; however, the definition remained unpublished since the invariant of (n + 1) variables itself was conjecturally complete.

      We begin with the group figure — the free group in generators a1, . . . , t1, . . . , tn and denote by figure the quotient sets of right residual classes {aj}\G for i = 1, . . . , n.

      Definition 2.18. An extended virtual n-system is a set of elements figure.

      Now we construct an invariant figure which takes values in extended virtual n-systems. The construction follows the same pattern as in the case of the f invariant, but with a different approach to virtual crossings. We begin with a system figuree, . . . , efigure and process the crossings one by one.

      To be precise, consider a crossing corresponding to an i-th generator or its inverse: either σi, ζi or figure. Assume that the left strand of this crossing originates from the point (p, 1), and the right one originates from the point (q,

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