Essential Concepts in MRI. Yang Xia

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Essential Concepts in MRI - Yang Xia

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I = 0, then the nucleus has no spin and cannot be observed by NMR (e.g., there is no NMR for 12C, even though each 12C nucleus contains six protons). If I > 0, the nucleus will have an associated magnetic dipole moment µ, given by

      The total number of the allowed spin states for a given nucleus is a discrete value, 2I + 1, which ranges from –I, –I + 1, –I + 2, …, to I. (It is another quantum mechanical concept that we need to cite in the classical description of nuclear magnetic resonance.) These values can be written as mI, the azimuthal quantum number. Hence, a nucleus with

       I = 1/2 has two spin states, mI = –1/2 and mI = 1/2. These two spin states are commonly illustrated in quantum mechanics by a two-level energy diagram as in Figure 2.2a, which we will discuss more in Chapter 3. Since there are only two spin states, we may use an arrow to describe the spin-1/2 particles. The mI = –1/2 state is called spin down (↓) while the mI = 1/2 state is called spin up (↑). The spin-down state has higher energy than the spin-up state, hence is the upper level in the energy level diagram (Figure 2.2a).Figure 2.2 The application of an external magnetic field B0 causes (a) a spin-1/2 system to have two discrete energy levels, and (b) a spin-1 system to have three energy levels. Each energy level can be labeled by the individual spin state.

       I > 1/2 has nuclear quadrupole moments that produce splitting of the resonant lines or line-broadening effects. For example, a deuteron (2H) has I = 1, which would have three spin states, corresponding to mI = –1, 0, 1. These three spin states can be used to label a three-level energy diagram as in Figure 2.2b. A quantum mechanical description must be used to understand the behavior of any spin with an angular momentum larger than 1/2.

Isotope Abundance (%) Spin γ (108 rad s-1 T-1) Relative sensitivity Resonance frequency f0 at 1T (MHz)
1H 99.9844 1/2 2.6752 1.00 42.577
2H 0.0156 1 0.4107 0.00964 6.536
13C 1.108 1/2 0.6726 0.0159 10.705
19F 100 1/2 2.5167 0.834 40.055
31P 100 1/2 1.0829 0.0664 17.235

      2.3 THE TIME EVOLUTION OF NUCLEAR MAGNETIC MOMENT

      Now look at the situation when one places a single nucleus in an externally applied magnetic field B0. Because of the dipole moment, the nucleus (which is represented by a magnetic moment µ) will interact with the external field B0, from which the energy of the nucleus in the field will be given by a dot product

      Since the nucleus also has an angular momentum, it experiences a torque, which can be expressed as a cross product, µ × B0. Since this torque is equal to the time derivative of the angular momentum, by quoting Newton’s second law, we have

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